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Alfred topographic maps

Click on a map to view its topography, its elevation and its terrain.

Alfred

United States > New York > Allegany County > Alfred

The elevation of Alfred is about 1,700 feet (520 m) but rises to a high point of 2,355 feet (718 m) at the summit of Jericho Hill just south of the village. The hills greatly affect the weather in the region, which results in quick changes as well as different conditions in neighboring valleys.

Average elevation: 604 m